(x+12)(x+2)=x^2+168

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Solution for (x+12)(x+2)=x^2+168 equation: 



(x+12)(x+2)=x^2+168

We move all terms to the left:

(x+12)(x+2)-(x^2+168)=0

We get rid of parentheses

-x^2+(x+12)(x+2)-168=0

We multiply parentheses ..

-x^2+(+x^2+2x+12x+24)-168=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+2x+12x+24)-168=0

We get rid of parentheses

-1x^2+x^2+2x+12x+24-168=0

We add all the numbers together, and all the variables

14x-144=0

We move all terms containing x to the left, all other terms to the right

14x=144

x=144/14

x=10+2/7

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